MULTIPLE CHOICE QUESTIONS:

MULTIPLE CHOICE QUESTIONS: (MCQ’s)

1. If  x1 ,x2 ,x3 , …… xn are the observations of a given data. Then the mean of the observations will be____
(a) Sum of observations/Total number of observations 
(b) Total number of observations/Sum of observations
(c) Sum of observations + Total number of observations
(d) None of the above

2. If the mean of frequency distribution is 7.5 and ∑fi xi = 120 + 3k, ∑fi = 30, then k is equal to____
(a) 40
(b) 35
(c) 50
(d) 45

3. The mode and mean is given by 7 and 8, respectively. Then the median is_____
(a) 1/13
(b) 13/3
(c) 23/3
(d) 33

4. The mean of the data: 4, 10, 5, 9, 12 is______
(a) 8
(b) 10
(c) 9
(d) 15

5. The median of the data 13, 15, 16, 17, 19, 20 is_____
(a) 30/2
(b) 31/2
(c) 33/2
(d) 35/2

6. If the mean of first n natural numbers is 15, then the value of n is_____
(a) 23
(b)2 4
(c) 29
(d) 26

7. If Arithmetic Mean  of a, a+3 , a+6,  a+9 and a+12  is 10, then a is equal to_____
(a) 1
(b) 2
(c) 3
(d) 4

8. The class interval of a given observation is 10 to 15, then the classmark for this interval will be_____
(a) 11.5
(b) 12.5
(c) 12
(d) 14

9. If the sum of frequencies is 24, then the value of x in the observation: x, 5, 6, 1, 2, will be______
(a) 4
(b) 6
(c) 8
(d) 10

10.The mean of following distribution is_____

xi 11 14 17 20
fi 3 6 8 7

(a) 15.6
(b) 17
(c) 14.8
(d) 16.4

11.The mean of   X: 4 ,6 ,8 , 10, 12.and  F: 1 , 5, 10, 15, 20. will be ___

(a) 11.6     
(b) 12.5   
(c) 13   
(d) 12.6

12.The mean of this distribution is 6. The value of y will be___

X:  2, 4 ,6  ,10 , y + 5 .

F: 3 , 2 , 3 , 1 ,  2 .

(a) 7  
(b) 12    
(c) 3   
(d) 6

13.____of a distribution is the value of the variable which divides it into two equal parts

(a) medium   
(b) median   
(c) mean   
(d) mode

14.If n is odd then median is the value of ____ observation.

(a) (n + 2)/1 th
(b)  (n −1)/2 th
(c) (n )/2 th   
(d)  (n + 1)/2 th

15.The median of the marks obtained in a test of 50 marks by 9 children will be___

(a) 32  
(b) 52   
(c) 42   
(d) 22

16. Recollect the median formula.The alphabet f stands for ____

(a) lower limit of median class
(b) frequency of median class
(c) size of median class
(d) cumulative frequency of class preceding the median class

17.The ___or modal value of a distribution is that value of a variable for
which the frequency is maximum

(a) mean 
(b) mode   
(c) median 
(d) none of these

18.For computation of mode for a continuous frequency distribution.
The first step will be ___

(a) find the class of maximum frequency
(b) find the width of modal class
(c) obtain the continuous frequency distribution
(d) put the values in the formula

19.To find median of a continuous frequency distribution the first step is ____

(a) prepare the cumulative frequency column
(b) obtain the frequency distribution
(c) use the formula
(d) none of these

20.The third method besides direct and short cut method will be ___ method

(a) step deviation
(b) step up
(c) step down  
(d) fast track

Answers. + Clues

 1 : (a)  (Text book)

 2 : (b)   Use Direct Method formula of mean

 3 : (c)   Use the formula  3Median = Mode +2Mean

 4 : (a)   Use Mean formula

5 : (c)    Here n is even (Textbook) (14.4)

6 : (c)  Mean = [n (n + 1)/2]/n = 15

 7 : (d) Use Mean formula

 8 : (b) Use class mark formula 

9 : (d)  Add all the frequencies and  it will be equal to 24

 10 : (d) Use Mean formula

11: (d)   Use Mean formula

12(a):  Use Mean formula

13:(b)  Definition of median

14: (d) Summary

15: (a)  Since 9 is an odd number.So median will be ( n+1)/2

16; (d)  Formula of Median

17: (b) Definition of mode

18: (c)   Order of putting values before writing the formula

19. (b) Steps of median formula

20: (a) Three methods of finding mean