EXERCISE 1.4

1.4 Revisiting Rational Numbers:
Theorem 1.5:
Let x be a rational number whose decimal expansion terminates. Then x can be expressed in the form \frac { p }{ q }  , where p and q are co prime, and the prime factorisation of q is of the form 2n 5n, where n, m are non-negative integers.

Theorem 1.6:
Let x = \frac { p }{ q }  be a rational number, such that the prime factorisation of q is of the form  2n 5n, where n, m are non-negative integers. Then x has a decimal expansion which terminates.

Theorem 1.7
Let x = \frac { p }{ q } be a rational number, such that the prime factorisation of q is of the form 2n 5n, where n, m are non-negative integers. Then x has a decimal expansion which is non-terminating repeating (recurring).

EXERCISE 1.4

1. Without actually performing the long division, state whether the following rational numbers will have a terminating decimal expansion or non-terminating repeating decimal expansion

Sol: We know that for terminating decimal expansion of a rational number of form  p/q , q must be  of the. form 2m × 5n

2.Write down the decimal expansions of those rational numbers in  Above which have terminating decimal expansions.

Sol:

(i) (13/3125) = (13/55 ) = 13 × (25/(25 x 55 )) = (416/105) = 0.00416

(ii) (17/8) = (17/23 ) = 17 × (53/(23 x 53 ) = 17 × (53/103 ) = (2125/103 ) = 2.125

(iv) (15/1600) = (15/24 ) × 102 = 15 × (54 / (24 x 54)) × 102 = (9375 / 106 ) = 0.009375

(vi) 23/(23 52 ) = 23 × 53 × (22 /(23 x 52 ) × 53 × 23 = (11500/ 103 ) = 0.115

(viii) 6/15 = 2/5 = 2 × 2/5 ×2 = 4/10 = 0.4

(ix) 35/50 = 7/10 = 0.7

3. The following real numbers have decimal expansions as given below. In each case, decide whether they are rational or not. If they are rational, and of the form pq you say about the prime factors of q.
(i) 43.123456789

(ii) 0.120120012000120000…
(iii) 43.123456789

Sol: (i) Since this number has a terminating decimal expansion, it is a rational number of the form \frac { p }{ q }  p, and q is of the form  2m × 5 n.

(ii) The decimal expansion is neither terminating nor recurring. Therefore, the given number is an irrational number.

(iii) Since the decimal expansion is non-terminating recurring, the given number is a rational number of the form \frac { p }{ q }  , and q is not of the form 2m × 5n